Trump reveals details of meeting with Zelensky in the US
27 December 2025 08:27
The administration of US President Donald Trump has confirmed that the American leader will meet with Ukrainian President Volodymyr Zelenskyy in Florida on December 28.
This is reported by "Komersant Ukrainian" with reference to the White House schedule.
It is noted that the bilateral meeting will be held in Palm Beach at 15:00 local time (23:00 Kyiv time).
Trump’s private residence Mar-a-Lago is located near this resort, where, according to the schedule, he arrived for the weekend.
What preceded it
On Friday, December 26, it became known that Donald Trump would meet with Volodymyr Zelenskyy on Sunday, December 28, at his Mar-a-Lago residence in Florida.
At the same time, Zelenskyy noted that during his meeting with his American counterpart, Donald Trump would definitely raise the issue of territories. According to Zelenskyy, he will discuss both Donbas and the Zaporizhzhia nuclear power plant with Trump.
For his part, Trump expressed cautious optimism about a peace deal during Ukrainian President Volodymyr Zelenskyy’s visit to his Mar-a-Lago club. According to him, Ukraine and Russia are committed to a peaceful settlement, but are still acting with caution.
Zelenskyy also said whether Europeans would attend his meeting with Trump.
In addition, Zelenskyy later said that the US president could come to Ukraine to support a peace agreement to end the war. Moreover, according to Volodymyr Zelenskyy, White House special envoy Steve Witkoff and US President’s son-in-law Jared Kushner are ready to visit Ukraine.
